# How do you find the Vertical, Horizontal, and Oblique Asymptote given #(x^2+1)/ (3x-2x^2)#?

##### 1 Answer

Oct 17, 2017

#### Answer:

Vertical asymptote

Horizontal asymptote

No slant asymptote.

#### Explanation:

Vertical Asymptote: Equate Denominator to zero.

Horizontal asymptote:

Since degrees of denominator and numerator are same, horizontal asymptote is obtained by dividing leading coefficients of highest degree numerator and denominator.

Slant or oblique asymptote :

Since numerator is not one degree above the denominator polynomial, there is slant or oblique asymptote.

graph{(x^2+1)/(3x-2x^2) [-10, 10, -5, 5]}