# How do you find the Vertical, Horizontal, and Oblique Asymptote given #y = (2x^2 - 11)/( x^2 + 9)#?

##### 1 Answer

Nov 10, 2016

Only a horizontal asymptote

#### Explanation:

As

Also observe that the denominator

Hence we have only a horizontal asymptote

graph{(y-(2x^2-11)/(x^2+9))(y-2)=0 [-10, 10, -5, 5]}