# How do you find the vertical, horizontal or slant asymptotes for (x^2 + 3) / (x^2 - 4)?

Mar 9, 2016

#### Answer:

VA: $x = \pm 2$
HA: $y = 1$ graph{(x^2+3)/(x^2-4) [-7.024, 7.024, -3.51, 3.514]}

#### Explanation:

Vertical Asymptote: Take denominator and set it equal to 0 and solve for x. ${x}^{2} - 4 = 0 \to {x}^{2} = 4 \to x = \pm 2$
Horizontal Asymptote:$y = \lim x \to \pm \infty \left({x}^{2} / {x}^{2}\right) \to y = 1$