How do you find the volume of concentrated 18M sulfuric acid to prepare 250mL of a 6.0M solution?

1 Answer
Mar 4, 2017

Answer:

We use the relationship: #"concentration"="Moles of solute"/"Volume of solution"#, and get under #100*mL# of conc. acid.

Explanation:

We require #250*mL# of a #6.0*mol*L^-1# solution (with respect to #H_2SO_4)#.

With respect to #H_2SO_4#, this represents a molar quantity of #0.250*Lxx6.0*mol*L^-1=1.50*mol#.

If the mother solution has a #18*mol*L^-1# concentration, then we solve the quotient, #(1.50*cancel(mol))/(18*cancel(mol)*cancel(L^-1))xx1000*mL*cancel(L^-1)=??*mL#.

Alternatively we could use the following formula for the molar equivalence:

#C_1V_1=C_2V_2#.............

#"Important, so get it right................."#

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