How do you find the x and y intercept given #2x-3y-12=0#?

1 Answer
Oct 27, 2015

Answer:

#x#-intercept: #(6,0)#
#y#-intercept: #(0,-4)#

Explanation:

The #x#-intercept is where the graph crosses the #x# axis, which is where #y=0#. Similarly, the #y#-intercept is where the graph crosses the #y# axis, or where #x=0#.

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To find the intercept points, plug in #0# for either #x# or #y# and solve for the other. Lets start with the #x#-intercept.

#2x-3(0)-12 = 0#

Add #12# to both sides.

#2x=12#

Divide both sides by #2#.

#x=6#

So the ordered pair for the #x#-intercept is;

#(6,0)#

Now do the same with the #y#-intercept.

#2(0)-3y-12=0#

Again, add #12# to each side.

#-3y=12#

This time divide by #-3#.

#y=-4#

So the ordered pair for the #y#-intercept is;

#(0,-4)#