# How do you find the x and y intercept given 2x-3y-12=0?

Oct 27, 2015

$x$-intercept: $\left(6 , 0\right)$
$y$-intercept: $\left(0 , - 4\right)$

#### Explanation:

The $x$-intercept is where the graph crosses the $x$ axis, which is where $y = 0$. Similarly, the $y$-intercept is where the graph crosses the $y$ axis, or where $x = 0$.

To find the intercept points, plug in $0$ for either $x$ or $y$ and solve for the other. Lets start with the $x$-intercept.

$2 x - 3 \left(0\right) - 12 = 0$

Add $12$ to both sides.

$2 x = 12$

Divide both sides by $2$.

$x = 6$

So the ordered pair for the $x$-intercept is;

$\left(6 , 0\right)$

Now do the same with the $y$-intercept.

$2 \left(0\right) - 3 y - 12 = 0$

Again, add $12$ to each side.

$- 3 y = 12$

This time divide by $- 3$.

$y = - 4$

So the ordered pair for the $y$-intercept is;

$\left(0 , - 4\right)$