How do you find the x and y intercept of #-2x+5y=20#?

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Answer 1 · 2017-03-30T22:37:52

See the entire solution process below:

Y-Intercept)

To find the y-intercept, set #x# equal to #0# and solve for #y#:

#-2x + 5y = 20# becomes:

#(-2 * 0) + 5y = 20#

#0 + 5y = 20#

#5y = 20#

#(5y)/color(red)(5) = 20/color(red)(5)#

#(color(red)(cancel(color(black)(5)))y)/cancel(color(red)(5)) = 4#

#y = 4#

The y-intercept is #4# or #(0, 4)#

X-Intercept)

To find the x-intercept, set #y# equal to #0# and solve for #x#:

#-2x + 5y = 20# becomes:

#-2x + (5 * 0) = 20#

#-2x + 0 = 20#

#-2x = 20#

#(-2x)/color(red)(-2) = 20/color(red)(-2)#

#(color(red)(cancel(color(black)(-2)))x)/cancel(color(red)(-2)) = -10#

#x = -10#

The x-intercept is #-10# or #(-10, 0)#