Question

How do you find the x and y intercept of `4x + 4y = 12`?

Answer 1

Intercept on `x`-axis is `3` and intercept on `y`-axis is also `3`.

Explanation:

In `4x+4y=12`, we can find intercept on `x`-axis by putting `y=0` and intercept on `y`-axis by putting `x=0`.

Hence intercept on `x`-axis is `4x+4xx0=12` or `4x=12` or `x=3`.

and intercept on `y`-axis is `4xx0+4y=12` or `4y=12` or `y=3`.

Alternatively if intercepts on `x`-axis and `y`-axis are `a` and `b` respectively, then equation of line is `x/a+y/b=1`. Hence, we can also find intercepts on `x`-axis and `y`-axis by converting the equation in this form.

Now `4x+4y=12hArr(4x)/12+(4y)/12=1` or

`x/3+y/3=1` and hence again we get that intercept on `x`-axis is `3` and intercept on `y`-axis is also `3`.