How do you find the x and y intercept of #4x + 4y = 12#?

1 Answer
Jul 2, 2016

Answer:

Intercept on #x#-axis is #3# and intercept on #y#-axis is also #3#.

Explanation:

In #4x+4y=12#, we can find intercept on #x#-axis by putting #y=0# and intercept on #y#-axis by putting #x=0#.

Hence intercept on #x#-axis is #4x+4xx0=12# or #4x=12# or #x=3#.

and intercept on #y#-axis is #4xx0+4y=12# or #4y=12# or #y=3#.

Alternatively if intercepts on #x#-axis and #y#-axis are #a# and #b# respectively, then equation of line is #x/a+y/b=1#. Hence, we can also find intercepts on #x#-axis and #y#-axis by converting the equation in this form.

Now #4x+4y=12hArr(4x)/12+(4y)/12=1# or

#x/3+y/3=1# and hence again we get that intercept on #x#-axis is #3# and intercept on #y#-axis is also #3#.