How do you find the x and y intercept of #y-3/5x-12#?

1 Answer
May 28, 2017

Answer:

Assumption: The expression should be an equation and of the form
#y=3/5x-12#

y-intercept#->(x,y)=(0,-12)#
x-intercept#->(x,y)=(20,0)#

Explanation:

y-intercept is the same as the constant #->y=-12#

That is because the y-intercept is at #x=0#
#y=3/5(0)-12" "=" "12#

y-intercept#->(x,y)=(0,-12)#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
x-intercept is at #y=0#

#=>y=0=3/5x-12#

Add 12 to both sides

#12=3/5x#

Multiply both sides by 5/3

#5/3xx 12=3/5xx5/3xx x#

#5xx12/3=1xx1xx x#

#20=x#

x-intercept#->(x,y)=(20,0)#