# How do you find the x and y intercept of y-3/5x-12?

May 28, 2017

#### Answer:

Assumption: The expression should be an equation and of the form
$y = \frac{3}{5} x - 12$

y-intercept$\to \left(x , y\right) = \left(0 , - 12\right)$
x-intercept$\to \left(x , y\right) = \left(20 , 0\right)$

#### Explanation:

y-intercept is the same as the constant $\to y = - 12$

That is because the y-intercept is at $x = 0$
$y = \frac{3}{5} \left(0\right) - 12 \text{ "=" } 12$

y-intercept$\to \left(x , y\right) = \left(0 , - 12\right)$

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x-intercept is at $y = 0$

$\implies y = 0 = \frac{3}{5} x - 12$

Add 12 to both sides

$12 = \frac{3}{5} x$

Multiply both sides by 5/3

$\frac{5}{3} \times 12 = \frac{3}{5} \times \frac{5}{3} \times x$

$5 \times \frac{12}{3} = 1 \times 1 \times x$

$20 = x$

x-intercept$\to \left(x , y\right) = \left(20 , 0\right)$