How do you find the x and y intercepts for $-2x+3y=6$ ?

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Answer 1 · 2016-05-17T13:26:32

Intercept on $x$ axis is $-3$ and

intercept on $y$ axis is $2$ .

For finding $x$ and $y$ intercepts of $-2x+3y=6$

Let us first put $y=0$ (to find intercepts on $x$ axis)

or $-2x+0=6$ or $x=-3$ .

Hence, intercept on $x$ axis is $-3$

For intercepts on $y$ axis, put $x=0$ i.e.

$3y=6$ or $y=2$

Hence, intercept on $y$ axis is $2$ .

The other way is to convert equation in the form $x/a+y/b=1$ , where $a$ is intercept on $x$ axis and $b$ is intercept on $y$ axis.

As $-2x+3y=6$ , dividing by $6$ we get

$(-2x)/6+(3y)/6=1$ or $x/(-3)+y/2=1$

Hence, $-3$ is intercept on $x$ axis and $2$ is intercept on $y$ axis.

graph{-2x+3y=6 [-10, 10, -5, 5]}

How do you find the x and y intercepts for -2x+3y=6-2x+3y=6?