How do you find the x and y intercepts for #-2x+3y=6#?

1 Answer
May 17, 2016

Answer:

Intercept on #x# axis is #-3# and

intercept on #y# axis is #2#.

Explanation:

For finding #x# and #y# intercepts of #-2x+3y=6#

Let us first put #y=0# (to find intercepts on #x# axis)

or #-2x+0=6# or #x=-3#.

Hence, intercept on #x# axis is #-3#

For intercepts on #y# axis, put #x=0# i.e.

#3y=6# or #y=2#

Hence, intercept on #y# axis is #2#.

The other way is to convert equation in the form #x/a+y/b=1#, where #a# is intercept on #x# axis and #b# is intercept on #y# axis.

As #-2x+3y=6#, dividing by #6# we get

#(-2x)/6+(3y)/6=1# or #x/(-3)+y/2=1#

Hence, #-3# is intercept on #x# axis and #2# is intercept on #y# axis.

graph{-2x+3y=6 [-10, 10, -5, 5]}