How do you find the x and y intercepts for #y=3x-5#?

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Answer 1 · 2018-05-03T02:00:50

x-intercept#=5/3# and y-intercept#=-5#

Reduce the given equation to #x/a+y/b=1# where #a# and #b# are x and y intercepts respectively.

Given equation is

#rarry=3x-5#

#rarr3x-y=5#

#rarr(3x)/5-y/5=1#

#rarrx/(5/3)+(y/(-5))=1#.....[1]

Comparing [1] by #x/a+y/b=1# we get #a=5/3 and b=-5#

So, x-intercept#=5/3# and y-intercept#=-5#