How do you find the x and y intercepts for #y=3x-5#?

1 Answer
May 3, 2018

Answer:

x-intercept#=5/3# and y-intercept#=-5#

Explanation:

Reduce the given equation to #x/a+y/b=1# where #a# and #b# are x and y intercepts respectively.

Given equation is

#rarry=3x-5#

#rarr3x-y=5#

#rarr(3x)/5-y/5=1#

#rarrx/(5/3)+(y/(-5))=1#.....[1]

Comparing [1] by #x/a+y/b=1# we get #a=5/3 and b=-5#

So, x-intercept#=5/3# and y-intercept#=-5#