How do you find the x and y intercepts for #y= - 6/5x + 6#?

1 Answer
Mar 25, 2018

Answer:

#x#-intercept at 5,
#y#-intercept at -6.

Explanation:

Since this is a linear function with a #b#-value and a slope, it must cross the #x# and #y# axes at some point.

To solve for the #y#-intercept, let #x# = #0#:

#y# = #-(6/5)#(#0#)+6
#y# = 6

To solve for the #x# - intercept, let #y# = #0#:

#0#= #-(6/5)(x)#+6
#-6=-(6/5)(x)#
#-30=-6x#
#x=5#