How do you find the x and y intercepts for #y=x-2#?

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Answer 1 · 2017-01-23T03:43:45

The y-intercept is #-2# and the point is #(0,-2)#.

The x-intercept is #2#, and the point is #(2,0)#.

#y=x-2# is in point-slope form #y=mx+b#, where #m# is the slope and #b# is the y-intercept. The y-intercept is the value of #y# when #x# is #0#.

For #y=x-2#, the y-intercept is #-2# and the point is #(0,-2)#.

To find the x-intercept, make #y# equal to zero and solve for #x#.

#0=x-2#

Add #2# to both sides.

#2=x#

The x-intercept is #2#, and the point is #(2,0)#.