How do you find the x- and y-intercepts of y=-7x-3?

Dec 11, 2016

The x- and y-intercepts are (0, -3) and ($- \frac{3}{7}$, 0)

Explanation:

The $y$-intercept is where $x = 0$. Substituting $0$ for $x$ in the equation and solving for $y$ gives:

$y = \left(- 7 \times 0\right) - 3$

$y = 0 - 3$

#y = -3

So, the y-intercept with x = 0 and y = -3 is: (0, -3)

The $x$-intercept is where $y = 0$. Substituting $0$ for $y$ in the equation and solving for $x$ gives:

$0 = - 7 x - 3$

$0 + 3 = - 7 x - 3 + 3$

$3 = - 7 x - 0$

$3 = - 7 x$

$\frac{3}{-} 7 = \frac{- 7 x}{-} 7$

$- \frac{3}{7} = \frac{\cancel{- 7} x}{\cancel{- 7}}$

$x = - \frac{3}{7}$

So, the x-intercept with y = 0 and x = -3/7 is: ($- \frac{3}{7}$, 0)