How do you find the x- and y-intercepts of #y=-7x-3#?

1 Answer
Dec 11, 2016

Answer:

The x- and y-intercepts are (0, -3) and (#-3/7#, 0)

Explanation:

The #y#-intercept is where #x = 0#. Substituting #0# for #x# in the equation and solving for #y# gives:

#y = (-7 xx 0) - 3#

#y = 0 - 3#

#y = -3

So, the y-intercept with x = 0 and y = -3 is: (0, -3)

The #x#-intercept is where #y = 0#. Substituting #0# for #y# in the equation and solving for #x# gives:

#0 = -7x - 3#

#0 + 3 = -7x - 3 + 3#

#3 = -7x - 0#

#3 = -7x#

#3/-7 = (-7x)/-7#

#-3/7 = (cancel(-7)x)/cancel(-7)#

#x = -3/7#

So, the x-intercept with y = 0 and x = -3/7 is: (#-3/7#, 0)