How do you find the x intercept for #f(x)=2log4(x)#?

1 Answer
Dec 17, 2015

Solve for #x# in #f(x) = 0# to find that the #x# intercept occurs at
#x = 1#.

Explanation:

An #x#-intercept occurs where #f(x) = 0#, and so to find any #x#-intercepts, we simply solve for #x# in that equation.

We will be proceeding under the assumption that the question is regarding the base-#4# log of #x# (as opposed to the base #10# or base #e# log of #4x#).

Using the property that #a^(log_a(x)) = x# we get

#2log_4(x) = 0#

#=> log_4(x) = 0#

#=> 4^(log_4(x)) = 4^0#

#=> x = 1#