Question

How do you find the x intercept for `f(x)=2log4(x)`?

Answer 1

Solve for `x` in `f(x) = 0` to find that the `x` intercept occurs at
`x = 1`.

Explanation:

An `x`-intercept occurs where `f(x) = 0`, and so to find any `x`-intercepts, we simply solve for `x` in that equation.

We will be proceeding under the assumption that the question is regarding the base-`4` log of `x` (as opposed to the base `10` or base `e` log of `4x`).

Using the property that `a^(log_a(x)) = x` we get

`2log_4(x) = 0`

`=> log_4(x) = 0`

`=> 4^(log_4(x)) = 4^0`

`=> x = 1`