How do you find the x intercept of #f(x)=sqrt(x+3)#? Algebra Radicals and Geometry Connections Graphs of Square Root Functions 1 Answer GiĆ³ Jun 1, 2015 When #x=-3# then #y=f(-3)=sqrt(-3+3)=0# So the x intercept is at #x=-3#. Answer link Related questions What are Graphs of Square Root Functions? How do you graph square root functions? How do you translate graphs of square root functions? What is the parent graph of a square root function? How do you graph #f(x)=\sqrt{x}+4#? What is the domain and range of the parent function #f(x)=\sqrt{x}# ? What is the ordered pair of the origin of the square root function #g(x)=\sqrt{x+4}+6#? How do you graph #y = \sqrt{4x+4}#? How do you graph #y = 2\sqrt{2x+3}+1#? How do you graph #f(x)=sqrt(x-3)+4#? See all questions in Graphs of Square Root Functions Impact of this question 2184 views around the world You can reuse this answer Creative Commons License