How do you find the y intercept, axis of symmetry and the vertex to graph the function #f(x)=-4x^2#?

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Answer 1 · 2018-01-17T12:58:41

Vertex is at #(0,0)#, y intercept is #y=0 or (0,0)# and
axis of symmetry is # x = 0 ; #

#f(x) = -4x^2 or f(x) = -4(x-0)^2+0 #

Comparing with vertex form of equation

#f(x) = a(x-h)^2+k ; (h,k)# being vertex we find

here #h=0 , k=0 :.# Vertex is at #(0,0)#

y intercept is found by putting #x=0# in the equation

#y = -4x^2 ; y=0 :.# y intercept is #y=0 or (0,0)#

Axis of symmetry is #x= h or x = 0 ; #

graph{-4x^2 [-10, 10, -5, 5]} [Ans]