# How do you find the y-intercept of y = x^2 + 6x + 9?

Dec 14, 2015

y-intercept $= 9$

#### Explanation:

The y-intercept is the value on the Y-axis where the equation crosses the Y-axis.

Since $x = 0$ for all point on the Y-axis
another way to say this is that:
the y-intercept is the value of $y$ when $x = 0$

Given $y = {x}^{2} + 6 x + 9$

when $x = 0$
$\textcolor{w h i t e}{\text{XXX}} y = {0}^{2} + 6 \times 0 + 9 = 9$

graph{x^2+6x+9 [-16.21, 12.27, -0.37, 13.87]}