# How do you find the zeroes for f(x) = (x-11)(x-5)(x-1)(x+5)?

May 29, 2015

The zeros of a function occur at those values of the argument for which the function has the value 0.

If $f \left(x\right) = \left(x - 11\right) \left(x - 5\right) \left(x - 1\right) \left(x + 5\right) = 0$

Then
$x - 11 = 0 \rightarrow x = 11$
or
$x - 5 = 0 \rightarrow x = 5$
or
$x - 1 = 0 \rightarrow x = 1$
or
$x + 5 = 0 \rightarrow x = - 5$