How do you find the zeros of f(x)=25x^2+10x-24?

1 Answer
Feb 28, 2017

Zeroes, or x-intercepts, are x = 4/5 and -6/5

Explanation:

When a math problem asks to find the "zeroes" of the equation, it is asking for the x-intercepts of the equation. In other words, you must set the equation equal to zero.

Step 1: Set it equal to zero
0=25x^2+10x-24

Step 2: Move the equation to the left side by subtracting 25x^2+10x-24

You're left with:
-25x^2-10x+24=0

Step 3: Factor!
(-5x+4)(5x+6)

Step 4: Set each side equal to zero.
-5x+4=0
5x+6=0

Step 5: Solve until x is alone on the left side.

x=4/5 and -6/5

Note: You can also double check by graphing and looking at the x-intercepts!
graph{y=25x^2+10x-24 [-7.9, 7.9, -3.95, 3.95]}