# How do you find the zeros of f(x)=2x (x - 3)^3 (x + 1) (4x - 2)?

Zeros of $f \left(x\right)$ are $x = 0 , 3 , - 1$ and $\frac{1}{2}$
Hence, 2x(x−3)^3(x+1)(4x−2) will be zero for $x = 0 , 3 , - 1$ or $\frac{1}{2}$.