# How do you find the zeros of  y = -1/5x^2 - 7/3x + 2/3  using the quadratic formula?

Dec 17, 2017

$\frac{- 35 \pm \sqrt{1345}}{6}$

#### Explanation:

−1/5x2−7/3x+2/3=0

The first thing to do is to simplify the equation replacing the reaction by the equivalent fraction with the same denominator:

−3/15x^2−35/15x+10/15=0

Now multiply both side by 15:

−3x^2−35x+10=0

now apply the second-degree formula:

$\frac{35 \pm \sqrt{{35}^{2} - 4 \left(- 3\right) \left(10\right)}}{2 \cdot \left(- 3\right)}$

$\frac{35 \pm \sqrt{1225 + 120}}{- 6}$

$\frac{- 35 \pm \sqrt{1345}}{6}$

Theres is now way to simplifiy sqrt(1345) so the solution may stay lique this.

In the case of the need of a number the solution are:

0.27904 and -11.9457