How do you find the zeros of # y = 4.5x^2 – 1.5x + 1.5# using the quadratic formula?

1 Answer
Jun 14, 2017

Answer:

#y# has no real zeroes, but its complex zeroes are #(3+-isqrt 87)/16#

Explanation:

The first thing we should check when trying to find the zeroes of a function is if its discriminant is greater than, equal to or less than zero.

#Delta_y = 1.5^2-4(4)(1.5)=-87/4#

#Delta_y < 0 therefore y# has no real roots.

However, we can still find its complex zeroes using the quadratic formula.

#x = (1.5+-sqrt(-1.5^2-4(4)(1.5)))/(2(4))=(3+-isqrt87)/16#