Question

How do you find the zeros, real and imaginary, of `y=x^2/4+1/2x-5/4` using the quadratic formula?

Answer 1

`x=-1+-2i`

Explanation:

`y=1/4x^2+1/2x-5/4`

`x=(-0.5+-sqrt(0.5^2-4(0.25)(1.25)))/(2(0.25)`

`x=(-0.5+-"i")/0.5=-1+-2i`