How do you find three consecutive even integers whose sum is 396?

Oct 23, 2017

$130 , 132 , 134$

Explanation:

let the even integers be

$2 n - 2 , 2 n , 2 n + 2 , n \in \mathbb{N}$

we have

$2 n - 2 + 2 n + 2 n + 2 = 396$

$6 n = 396$

$n = \frac{396}{6} = 66$

integers

$2 n = 2 \times 66 = 132$
$2 n - 2 = 130$

$2 n + 2 = 134$

check
130+132+134=396sqrt