# How do you find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126?

Jun 9, 2018

$24 , 25 , 26$

#### Explanation:

Let's call the smallest integer $n$. Then the next two consecutive integers are $n + 1$ and $n + 2$.

"Sum of twice the smallest and 3 times the largest is 126"

$2 \left(n\right) + 3 \left(n + 2\right) = 126$

$2 n + 3 n + 6 = 126$

$5 n + 6 = 126$

$5 n = 120$

$n = 24$

So the smallest integer is $24$.

The three consecutive integers are then: $24$, $25$, and $26$.