How do you find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126?

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Answer 1 · 2018-06-09T15:41:22

#24, 25, 26#

Let's call the smallest integer #n#. Then the next two consecutive integers are #n+1# and #n+2#.

"Sum of twice the smallest and 3 times the largest is 126"

#2(n) + 3(n+2) = 126#

#2n + 3n + 6 = 126#

#5n + 6 = 126#

#5n = 120#

#n = 24#

So the smallest integer is #24#.

The three consecutive integers are then: #24#, #25#, and #26#.