# How do you find three consecutive integers such that twice the smallest is 12 more than the largest?

Jan 22, 2016

Convert the conditions into an equation and solve to find that the three integers are: $14 , 15 , 16$

#### Explanation:

Suppose the three integers are $n$, $n + 1$ and $n + 2$

We are given:

$2 n = \left(n + 2\right) + 12$

Subtract $n$ from both sides to find:

$n = 2 + 12 = 14$

So the three integers are $14 , 15 , 16$.