How do you find three consecutive integers such that twice the smallest is 12 more than the largest?

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Answer 1 · 2016-01-22T00:24:19

Convert the conditions into an equation and solve to find that the three integers are: #14, 15, 16#

Suppose the three integers are #n#, #n+1# and #n+2#

We are given:

#2n = (n+2)+12#

Subtract #n# from both sides to find:

#n = 2+12 = 14#

So the three integers are #14, 15, 16#.