# How do you find three consecutive odd integers such that three times the first minus the second is one more than the third?

Three consecutive odd numbers are $7 , 9 , 11$
Let the three consecutive odd numbers are $2 n - 1 , 2 n + 1 , 2 n + 3$ In given condition 3(2n-1) - (2n+1) = (2n+3) +1 or 6n - 3 - 2n - 1 = 2n+4 or 2n= 8 or n=4 :. 2n-1=7 ; 2n+1=9 ; 2n+3=11So consecutive odd numbers are $7 , 9 , 11$[Ans]