# How do you find three consecutive odd integers whose sum is 13 more than twice the largest of the three?

##### 1 Answer

Jan 24, 2016

Interpret the description in terms of an unknown smallest integer

#15, 17, 19#

#### Explanation:

Suppose the three odd integers are

Their sum is:

#n + (n+2) + (n+4) = 3n+6#

#2(n+4)+13 = 2n+21#

From what we are told these two are equal:

#3n+6 = 2n+21#

Subtract

#n = 15#

So the three integers are:

#15, 17, 19#