# How do you find three consecutive odd integers whose sum is 5?

Three consecutive odd integers will be expressible as $n$, $n + 2$ and $n + 4$ where the least of the three integers is $n$.
This has sum $n + \left(n + 2\right) + \left(n + 4\right) = 3 n + 6 = 3 \left(n + 2\right)$ which is divisible by $3$.
The number $5$ is not divisible by $3$ so cannot be expressed as such a sum.