How do you find three consecutive odd integers, whose sum is 57?

2 Answers
May 21, 2018

Let the first and the smallest integer be #x-2#

Then... the second integer will be #x#

Then.... the third integer will be #x+2#

Now... their sum is #57#

#xcancel(-2)+x+x+cancel2=57#

You get

#3x=57#

#x=57/3#

#color(red)(x=19#( that's the second integer)

First integer
#x-2=19-2#

#color(red)(x-2=17#

Third integer
#x+2=19+2#

#color(red)(x+2=21#

May 21, 2018

Answer:

Three consecutive odd integers are #17,19,21#

Explanation:

Let the three consecutive odd integers are #2 x-1, 2 x+1,2 x+3#

Then , #2 x-1+2 x+1+2 x+3=57 or 6 x+3=57# or

# 6 x =54 :. x=9 , 2 x - 1= 17 , 2 x +1=19 , 2 x+3= 21 #

Three consecutive odd integers are #17,19,21# [Ans]