Question

How do you find two different parametric equations for rectangular equation given: y = 6x - 1?

Answer 1

There are infinitely many ways of parameterizing a curve:

Explanation:

The simplest parametrization is to put `x=t`, which gives:

`{ (x=t), (y=6t-1) :}`

Another option would be `6x=t`, giving:

`{ (x=t/6), (y=t-1) :}`

And as a bonus why not use `2x=6tt`

`{ (x=3t), (y=18t-1) :}`