How do you find unit vector of #a=(1, 2, -2)# in direction of #a#?
1 Answer
Aug 6, 2016
Explanation:
Divide by the length of the vector
#|| a || = sqrt(1^2+2^2+(-2)^2) = sqrt(1+4+4) = sqrt(9) = 3#
So the unit vector is:
#a/(|| a ||) = 1/3(1, 2, -2) = (1/3, 2/3, -2/3)#