How do you find unit vector of $a = (1, 2, - 2)$ $a=(1, 2, -2)$ in direction of $a$ $a$ ?

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Answer 1 · 2016-08-06T08:27:21

$\frac{a}{| | a | |} = (\frac{1}{3}, \frac{2}{3}, - \frac{2}{3})$ $a/(|| a ||) = (1/3, 2/3, -2/3)$

Divide by the length of the vector $a$ $a$ .

$| | a | | = \sqrt{1^{2} + 2^{2} + {(- 2)}^{2}} = \sqrt{1 + 4 + 4} = \sqrt{9} = 3$ $|| a || = sqrt(1^2+2^2+(-2)^2) = sqrt(1+4+4) = sqrt(9) = 3$

So the unit vector is:

$\frac{a}{| | a | |} = \frac{1}{3} (1, 2, - 2) = (\frac{1}{3}, \frac{2}{3}, - \frac{2}{3})$ $a/(|| a ||) = 1/3(1, 2, -2) = (1/3, 2/3, -2/3)$

How do you find unit vector of a=(1, 2, -2)a=(1,2,−2)a=(1, 2, -2) in direction of aaa?