# How do you find vertical, horizontal and oblique asymptotes for #f(x) = (3x^2 - 3x- 36) / (2x^2 + 9x +4) #?

##### 1 Answer

May 8, 2016

#### Answer:

Vertical asymptotes are

and horizontal asymptote

#### Explanation:

In

Hence vertical asymptotes are

As degree of numerator is equal to that of denominator in the algebraic expression, we have only horizontal asymptote given by

Had the degree of numerator just one greater than that of denominator, we would have oblique asymptote.

graph{(3x^2-3x-36)/(2x^2+9x+4) [-20, 20, -10, 10]}