# How do you find vertical, horizontal and oblique asymptotes for #f(x)=(x^2+5x+8) / (x+3)#?

##### 1 Answer

#### Answer:

#### Explanation:

Asymptotes of algebraic expressions are easy to find,

First of all **vertical asymptotes**, if denominator has a zero at a point but numerator does not have, we have an asymptote at that point.

In the given expression, we have denominator zero for

As regards **horizontal asymptote**, we have it at

If the degrees are equal, then we have a horizontal asymptote

If the degree of numerator is just one higher than that of denominator, say they are given by

Here the degree of numerator is

Hence

graph{(x^2+5x+8)/(x+3) [-40, 40, -20, 20]}