# How do you find vertical, horizontal and oblique asymptotes for #(x^3+1)/(x^2+3x)#?

##### 1 Answer

May 6, 2016

#### Answer:

Vertical asymptotes are

Oblique asymptote is

#### Explanation:

To find all the asymptotes for function

i.e.

As the highest degree of numerator is

Hence, Vertical asymptotes are

graph{(x^3+1)/(x^2+3x) [-10, 10, -5, 5]}