# How do you find vertical, horizontal and oblique asymptotes for y=3/(x-2)+1?

Nov 9, 2016

The vertical asymptote is $x = 2$
The horizontal asymptote is $y = 1$
There is no oblique asymptote.

#### Explanation:

As we cannot divide by $0$, the vertical asymptote is $x = 2$
And ${\lim}_{x \to \pm \infty} y = 1$
So $y = 1$is a horizontal asymptote.
There is no oblique asymptote as the degree of the numerator $=$ the degree of the denominator
graph{(y-1-3/(x-2))(y-1)=0 [-14.24, 14.24, -7.12, 7.12]}