How do you find x and y intercepts of # -3x + y = 6#?

1 Answer
Feb 20, 2017

Answer:

#x-"intercept" = (-2,0)#

#y-"intercept" = (0,6)#

Explanation:

All along the #x#-axis, the #y#-value is zero.

All along the #y#-axis, the #x#-value is zero.

TO find the #x#-intercept make #y=0#

#-3x +y =6#

#-3x +0 =6#

#x = -2" "rarr" the point is " (-2,0)#

TO find the #y#-intercept make #x=0#

#-3x +y = 6#

#0 +y =6#

#y=6" "rarr" the point is " (0,6)#