# How do you find y when x=12 if y is inversely proportional to x and y=2 when x=8?

Nov 3, 2014

Since $y$ is inversely proportional to $x$, we can wite

$y = \frac{k}{x}$,

where $k$ is a constant.

Since $y = 2$ when $x = 8$,

$2 = \frac{k}{8} \implies k = 16$

Now, we know the complete formula

$y = \frac{16}{x}$.

If $x = 12$, then

$y = \frac{16}{12} = \frac{4}{3}$.

I hope that this was helpful.