If y varies directly as x and inversely as the square of z and if #y=20#  when #x=50# and #z=5# how do you find y when #x=3# and #z=6#?  

1 Answer
May 9, 2018

Answer:

#y=5/6#

Explanation:

#"the initial statement is "ypropx/z^2#

#"to convert to an equation multiply by k the constant"#
#"of variation"#

#rArry=kxx x/z^2=(kx)/z^2#

#"to find k use the given condition"#

#y=20" when "x=50" and "z=5#

#y=(kx)/z^2rArrk=(yz^2)/x=(20xx25)/50=10#

#"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=(10x)/z^2)color(white)(2/2)|))#

#"when "x=3" and "z=6" then"#

#y=(10xx3)/36=30/36=5/6#