# How do you FOIL (2y - 5)(y + 9)?

=$2 {y}^{2} + 13 y - 45$
To foil $\left(2 y - 5\right) \left(y + 9\right)$ you first $2 y \times y$ and $2 y \times 9$ and $- 5 \times y$ and $- 5 \times 9$
giving $2 {y}^{2} + 18 y - 5 y - 45$
simplified=$2 {y}^{2} + 13 y - 45$