How do you foil #(3x+2)(2x+5)#?

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Answer 1 · 2015-08-26T05:03:24

#=color(blue)(6x^2+19x+10#

The expression is :# (3x+2)(2x+5)#

F O I L involves carrying out the below operations in the following order:

1) product of First terms :#(color(blue)(3x and 2x))#+

2)product of Outside terms:#(color(blue)(3x and 5))#+

3)product of Inside terms:#(color(blue)(2 and 2x))#+

4)product of Last terms:#(color(blue)(2 and5))#

1) #3x *2x=color(blue)(6x^2) +#

2) #3x * 5=color(blue)(15x)+#

3) #2 * 2x = color(blue)(4x)+#

4) #2 *5 = color(blue)10#

adding all the terms

#=color(blue)(6x^2 +15x +4x+10#
#=color(blue)(6x^2+19x+10#