How do you foil $(3 x + 2) (2 x + 5)$ $(3x+2)(2x+5)$ ?

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Answer 1 · 2015-08-26T05:03:24

$= 6 x^{2} + 19 x + 10$ $=color(blue)(6x^2+19x+10$

The expression is : $(3 x + 2) (2 x + 5)$ $(3x+2)(2x+5)$

F O I L involves carrying out the below operations in the following order:

1) product of First terms : $(3 x and 2 x)$ $(color(blue)(3x and 2x))$ +

2)product of Outside terms: $(3 x and 5)$ $(color(blue)(3x and 5))$ +

3)product of Inside terms: $(2 and 2 x)$ $(color(blue)(2 and 2x))$ +

4)product of Last terms: $(2 and 5)$ $(color(blue)(2 and5))$

1) $3 x \cdot 2 x = 6 x^{2} +$ $3x *2x=color(blue)(6x^2) +$

2) $3 x \cdot 5 = 15 x +$ $3x * 5=color(blue)(15x)+$

3) $2 \cdot 2 x = 4 x +$ $2 * 2x = color(blue)(4x)+$

4) $2 \cdot 5 = 10$ $2 *5 = color(blue)10$

adding all the terms

$= 6 x^{2} + 15 x + 4 x + 10$ $=color(blue)(6x^2 +15x +4x+10$
$= 6 x^{2} + 19 x + 10$ $=color(blue)(6x^2+19x+10$

How do you foil (3x+2)(2x+5)(3x+2)(2x+5)(3x+2)(2x+5)?