Question

How do you FOIL `(3x^2-6)(x^3-9)`?

Answer 1

`(3x^2-6)(x^3-9)=3x^5-27x^2-6x^3+54`

Problem: FOIL `(3x^2-6)(x^3-9)` .

FOIL stands for:

First: Multiply the first term in each binomial together.
Outer/Outside: Multiply the outer/outside term in each binomial together.
Inner/Inside: Multiply the inner/inside term in each binomial together.
Last: Multiply the last term in each binomial together.

`(3x^2-6)(x^3-9)` =

`(3x^2*x^3)+(3x^2*-9)+(-6*x^3)+(-6*(-9))` =

`3x^5-27x^2-6x^3+54`