How do you foil $(–7x – 11)(19x – 14)$ ?

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Answer 1 · 2015-08-28T17:41:25

$color(red)((–7x–11)(19x–14) = -133x^2 - 111x + 154)$

$"FOIL"$ stands for $"F"$ irst, $"O"$ uter, $"I"$ nner, $"L"$ ast.

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Your expression is $(–7x–11)(19x–14)$ .

So you take each product in turn and then add them up.

We multiply the $"F"$ irst term in both parentheses together:

$-7x×19x = -133x^2$

Then the $"O"$ uter terms

$-7x×(-14) = 98x$

Then the $"I"$ nner terms

$-11×19x= -209x$

And finally the $"L"$ ast terms.

$-11×(-14)=154$

Then we add them up to get our expression:

$(–7x–11)(19x–14)= -133x^2+98x-209x+154$

We combine like terms to get the answer:

$(–7x–11)(19x–14) = -133x^2 - 111x + 154$

How do you foil (–7x – 11)(19x – 14)(–7x – 11)(19x – 14)?