How do you foil #(–7x – 11)(19x – 14)#?

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Answer 1 · 2015-08-28T17:41:25

#color(red)((–7x–11)(19x–14) = -133x^2 - 111x + 154)#

#"FOIL"# stands for #"F"#irst, #"O"#uter, #"I"#nner, #"L"#ast.

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Your expression is #(–7x–11)(19x–14)#.

So you take each product in turn and then add them up.

We multiply the #"F"#irst term in both parentheses together:

#-7x×19x = -133x^2#

Then the #"O"#uter terms

#-7x×(-14) = 98x#

Then the #"I"#nner terms

#-11×19x= -209x#

And finally the #"L"#ast terms.

#-11×(-14)=154#

Then we add them up to get our expression:

#(–7x–11)(19x–14)= -133x^2+98x-209x+154#

We combine like terms to get the answer:

#(–7x–11)(19x–14) = -133x^2 - 111x + 154#