How do you foil #(7x + 7)(5x – 4)#?

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Answer 1 · 2015-08-26T07:07:41

#=color(blue)(35x^2+7x-28#

The expression is :# (7x+7)(5x-4)#

F O I L involves carrying out the below operations in the following order:

1) product of First terms :#(color(blue)(7x and 5x))#+

2)product of Outside terms:#(color(blue)(7x and -4))#+

3)product of Inside terms:#(color(blue)(7 and 5x))#+

4)product of Last terms:#(color(blue)(7 and -4))#

1) #7x*5x=color(blue)(35x^2) +#

2) #7x * -4=color(blue)(-28x)+#

3) #7 * 5x = color(blue)(35x)+#

4) #7 *-4 = color(blue)(-28#

adding all the terms

#=color(blue)(35x^2-28x+35x-28#
#=color(blue)(35x^2+7x-28#