How do you FOIL #(8x^3-7)(x^7-9)#?

1 Answer
Evan
Mar 12, 2018

#8x^10-7x^7-72x^3+63#

Explanation:

F - Firsts
O - Outers
I - Inners
L- Lasts

https://calculator.tutorvista.com/foil-calculator.html

Now, let's get started,

#(8x^3-7)(x^7-9)#

Multiply firsts,

#8x^3xxx^7=8x^10#

Multiply outers,

#8x^3xx-9=-72x^3#

Multiply inners,

#-7xxx^7=-7x^7#

Multiply lasts,

#-7xx-9=63#

Lastly add them all up,

#8x^10-7x^7-72x^3+63#

Related questions
See all questions in Multiplication of Polynomials by Binomials
Impact of this question
1088 views around the world
You can reuse this answer
Creative Commons License