How do you foil #(9x + 9)(3x + 3) #?

1 Answer
Aug 24, 2015

Answer:

#(9x+9)(3x+3)=(27x^2+54x+27)#

Explanation:

FOIL:
Sum of
#color(white)("XXX")#product of First terms, plus
#color(white)("XXX")#product of Outside terms, plus
#color(white)("XXX")#product of Inside terms, plus
#color(white)("XXX")#product of Last terms

#{: ("product of First terms", 9x*3x=, 27x^2), ("product of Outside terms",9x*3=,27x), ("product of Inside terms", 9*3x =, 27x), ("product of Last terms", 9*3=,27), (, ,), ("Sum", ,27x^2+54x+27) :}#