Question

How do you foil `(9x + 9)(3x + 3)`?

Answer 1

`(9x+9)(3x+3)=(27x^2+54x+27)`

Explanation:

FOIL:
Sum of
`color(white)("XXX")`product of First terms, plus
`color(white)("XXX")`product of Outside terms, plus
`color(white)("XXX")`product of Inside terms, plus
`color(white)("XXX")`product of Last terms

#{: ("product of First terms", 9x*3x=, 27x^2), ("product of Outside terms",9x*3=,27x), ("product of Inside terms", 9*3x =, 27x), ("product of Last terms", 9*3=,27), (, ,), ("Sum", ,27x^2+54x+27) :}#