How do you foil #(n-7)(3n-2)#?

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Answer 1 · 2015-08-26T03:57:38

#=color(blue)(3n^2-23n+14#

The expression is :# (n−7)(3n−2)#

F O I L involves carrying out the below operations in the following order:

1) product of First terms :#(color(blue)(n and 3n))#+

2)product of Outside terms:#(color(blue)(n and -2))#+

3)product of Inside terms:#(color(blue)(-7 and 3n))#+

4)product of Last terms:#(color(blue)(-7 and -2))#

1) #n *3n=color(blue)(3n^2) +#

2) #n * -2=-color(blue)(2n)+#

3) #-7 * 3n = color(blue)(-21n)+#

4) #-7 *-2 = color(blue)14#

adding all the terms

#=color(blue)(3n^2-2n-21n+14#
#=color(blue)(3n^2-23n+14#