# How do you foil (n-7)(3n-2)?

Aug 26, 2015

=color(blue)(3n^2-23n+14

#### Explanation:

The expression is : (n−7)(3n−2)

F O I L involves carrying out the below operations in the following order:

1) product of First terms :$\left(\textcolor{b l u e}{n \mathmr{and} 3 n}\right)$+

2)product of Outside terms:$\left(\textcolor{b l u e}{n \mathmr{and} - 2}\right)$+

3)product of Inside terms:$\left(\textcolor{b l u e}{- 7 \mathmr{and} 3 n}\right)$+

4)product of Last terms:$\left(\textcolor{b l u e}{- 7 \mathmr{and} - 2}\right)$

1) $n \cdot 3 n = \textcolor{b l u e}{3 {n}^{2}} +$

2) $n \cdot - 2 = - \textcolor{b l u e}{2 n} +$

3) $- 7 \cdot 3 n = \textcolor{b l u e}{- 21 n} +$

4) $- 7 \cdot - 2 = \textcolor{b l u e}{14}$

=color(blue)(3n^2-2n-21n+14
=color(blue)(3n^2-23n+14