How do you FOIL #(s^2+t)(s^2-t)#?

1 Answer
May 26, 2015

Given #color(red)((s^2+t))color(blue)((s^2-t))#

First terms: #color(red)(s^2) and color(blue)(s^2)#
Outside terms: #color(red)(s^2) and color(blue)((-t))#
Inside terms: #color(red)(t) and color(blue)(s^2)#
Last terms: #color(red)(t) and color(blue)(-t)#

The FOIL method is to
Sum

the product of the First terms (#s^2xxs^2 = s^4#)
the product of the Outside terms (#s^2xx(-t) = (-s^2t)#)
the product of the Inside terms (#t xx s^2 = s^2t#)
and
the product of the Last terms (#txx(-t) = (-t^2)#

For the given example this sum is #s^4-t^2#