How do you FOIL #(s^2+t)(s^2-t)#?
1 Answer
May 26, 2015
Given
First terms:
Outside terms:
Inside terms:
Last terms:
The FOIL method is to
Sum
the product of the First terms (
#s^2xxs^2 = s^4# )
the product of the Outside terms (#s^2xx(-t) = (-s^2t)# )
the product of the Inside terms (#t xx s^2 = s^2t# )
and
the product of the Last terms (#txx(-t) = (-t^2)#
For the given example this sum is