How do you FOIL #(s^2+t)(s^2+t)#?

1 Answer
Mar 18, 2018

Answer:

#s^4+2s^2t+t^2#

Explanation:

When you #FOIL# a set of factors (also called double distributing), we follow these steps:

#F# - First
#O# - Outer
#I# - Inner
#L# - Last

It may seem confusing with just variables, and the fact that the #s# is squared, but it works all the same.

After following the steps given by the acronym, we get:

#s^4+s^2t+s^2t+t^2#

Here we just combine like terms and get:

#s^4+2s^2t+t^2#