How do you foil #(x+3)^2 #?

1 Answer
May 24, 2018

Answer:

#x^2+6x+9#

Explanation:

First, let's rewrite the expression as

#(x+3)(x+3)#

Rewriting it in this form is what allows us to do FOIL, which stands for Firsts, Outsides, Insides, Lasts. This is the order we'll multiply in:

  • Multiply the first terms: #x*x=x^2#
  • Multiply the outside terms: #x*3=3x#
  • Multiply the inside terms: #3*x=3x#
  • Multiply the last terms: #3*3=9#

Now, we have the following:

#x^2+3x+3x+9#

Which can obviously be simplified to

#x^2+6x+9#

Hope this helps!